How do you calculate geosynchronous orbit?
How do you calculate geosynchronous orbit?
We can solve for re-s after substituting for G = 0.667 x 10-10 Nm2/kg2, Me= 6×1024 kg and T=24 h × (3600 s/h) = 8.64 ×104 s. re−s=(0. 667×6×8.64240×10−10+24+2×4)13 km. 667 × 6 × 8.64 2 40 × 10 − 10 + 24 + 2 × 4 ) 1 3 km (You might want to check the units.)
How do you calculate orbits?
The orbit formula, r = (h2/μ)/(1 + e cos θ), gives the position of body m2 in its orbit around m1 as a function of the true anomaly. For many practical reasons we need to be able to determine the position of m2 as a function of time.
What is geosynchronous satellite and calculate its height from Earth?
A geostationary satellite is a satellite which revolves around the Earth with exact same angular speed and direction as the Earth. Thus it appears stationary from Earth. ≈ 3.6 × 107 m or 36,000 km from the surface of Earth.
How do you calculate the time period of a geostationary satellite?
A geostationary orbit can only be achieved at an altitude very close to 35,786 km (22,236mi), and directly above the Equator. This equates to an orbital velocity of 3. 07km/s(1. 91mi/s) or an orbital period of 1,436 minutes, which equates to almost exactly one sidereal day or 23.
What is the mathematical relationship between distance and orbital period?
Kepler’s 3rd Law of Planetary Motion states that the square of the orbital period of a body orbiting around a larger body is proportional to the cube of the semi-major axis of the body’s orbit, which is basically the body’s distance from the larger body.
How do you calculate the altitude and velocity of a satellite in a geosynchronous orbit of Mars?
1 Answer
- Fc=m2v2r.
- Fg=GM1m2r2.
- m2v2r=GM1m2r2.
- 4π2r2T2=GM1r.
- r3=GM1T24π2.
What is the formula of height of satellite?
h = 3.6 x 107 m = 36000 km. The height of geostationary satellite from the surface of the earth is 36000 km. = 1.5 × 1011 m). Let the force on the rocket be zero at a distance x from the earth.
What is the velocity of a satellite in geosynchronous orbit?
The aptly titled geosynchronous orbit is described in detail: “At an altitude of 124 miles (200 kilometers), the required orbital velocity is just over 17,000 mph (about 27,400 kph). To maintain an orbit that is 22,223 miles (35,786 km) above Earth, the satellite must orbit at a speed of about 7,000 mph (11,300 kph).