What is the gram equivalent of K2Cr2O7?
What is the gram equivalent of K2Cr2O7?
Equivalent weight of K2Cr2O7 is 49 g/mol.
What is molecular weight & equivalent weight of K2Cr2O7?
Detailed Solution Potassium dichromate in an acidic medium is a strong oxidizer. It means it gains electrons during the redox reaction. The total number of electrons involved in this change is 6. Equivalent weight = molecular weight / no of e- = 294 / 6 = 49 g/mol.
How do you find the equivalent mass of K2Cr2O7 in the reaction?
The equivalent mass of K2Cr2O7= Total change in the oxidation number of CrFormula mass of KCrO=6294=49.
What is the equivalent weight of k2cro4?
(D) Infinite. The correct answer is (B) M/2. As given in the question: K2CrO4 reacts with AgNO3 to give Ag2CrO4.
How do you make 0.1 n K2Cr2O7?
Preparation of 0.1 N Potassium dichromate (K2Cr2O7) Solution
- Transfer 6 g of potassium dichromate (K2Cr2O7) to a platinum dish and dry at 120°C for 4 h. Cool in a desiccator.
- Place 4.9 g of the dried K2Cr2O7 in a 1-L volumetric flask, and.
- Add 100 mL of water.
- Store the solution in a glass-stoppered bottle.
How do you calculate gram equivalent?
Gram equivalent weight is equal to mass in grams numerically equal to Equivalent Weight. To calculate the Gram Equivalent Weight, we use the formula Eq = MW / n.
How do you calculate gram equivalent weight?
What is the equivalent weight of K2Cr2O7 in acidic medium if its molecular weight is taken as M?
Therefore the equivalent weight is =6M.
What is the molar mass of K2CrO4?
194.1896 g/molPotassium chromate / Molar mass
What is the percent composition of K2CrO4?
The percent composition of chromium in potassium chromate is 35.3495% .
How do you make 0.25 N K2Cr2O7?
Std. K2Cr2O7 , 0.25 N :- ‘Dissolve 12.259 gm K2Cr2O7 in 1 L distilled water.
What is the normality of K2Cr2O7?
The normality of potassium dichromate can vary from solution to solution. With regards to the number of equivalents of potassium dichromate per mole, for an acid-base reaction, the total number of equivalents will be 2. In redox reactions, the total number of equivalents per mole will be 6.